Which does not gives iodoform test:-

P h - O H | C H - C H_{3}

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P h - C | | O - C H_{3}

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I - C H_{2} - C | | O - H

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C H_{3} - C H_{2} - C | | O - O - C H_{3}

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Solution

The correct option is A $P h - O H | C H - C H_{3}$

The iodoform test is a test used to identify the presence of carbonyl compounds with the structure $R C O C H_{3}$ (ketone) and alcohols with the structure $R C H (O H) C H_{3}$
So in the given options A do not give iodoform test as it has a phenyl group.

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C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - O | | C - H (i); C H_{3} - O | | C - C H_{3} (i i); E t - O | | C - H (i i i)

C H_{3} - C H_{2} - C H_{2} - O | | C - H (i v); P h - O | | C - C H_{3} (v); P h - O | | C - P h (v i)

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

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