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Question

Which forms di-iodide on reaction with HI (excess)?
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A
I and II both
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B
II only
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C
I only
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D
none
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Solution

The correct option is A: I only


I will form di-iodide on reaction with excess HI.


In the first step, it will form OHCH2CH2CH2CH2CH2I

but then again on reaction with HI it will form ICH2CH2CH2CH2CH2I

NOTE:

In the other compound-II, the Lone pair electron is involved in the resonance hence it does not gives an iodized product.


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