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Question

Which is the smallest of all the chords of a circle passing through a given point in it?

A
Chord trisected at the point.
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B
Chord bisected at the point.
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C
Chord passing through the centre.
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D
Both (A)and (B)
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Solution

The correct option is B Chord bisected at the point.

Let C (O,r) is a circle and let M is a point within it where O is the centre and r is the radius of the circle.
Let CD is another chord passes through point M.
We have to prove that AB<CD.
Now join OM and draw OL perpendicular to CD.
In right angle triangle OLM,
OM is the hypotenuse.
So OM>OL
chord CD is nearer to O in comparison to AB.
CD>AB
AB<CD

Smallest one is the one bisected at the point.


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