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Coordination and Oxidation Number

Which of the ...

Question

Which of the following 3d-series transition metal exhibits the largest number of oxidation states?

A

Fe

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B

Mn

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C

Co

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D

V

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Solution

The correct option is B Mn
$\begin{matrix} V & M n & F e & C o 0 & 0 & 0 & 0 1 & 1 & 1 & 1 2 & 2 & 2 & 2 3 & 3 & 3 & 3 4 & 4 & 4 & 4 5 & 5 & 5 & 5 67 \end{matrix}$
Mn exhibits the largest number of oxidation states because it has electronic configuration $[(A r) 3 d^{5} 4 s^{2}],$
Hence maximum oxidation state of Mn is + 7

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Similar questions

Q. (i) Name the elements of

3 d

transition series which shows maximum number of oxidation states. Why does it show so?
(ii) Which transition metal of

3 d

series has positive

E_{(M^{2 +} / M)}^{o}

value and why?
(iii) Out of

{C r}^{3 +}

{M n}^{3 +}

, which is a stronger oxidizing agent and why?
(iv) Name a member of the Lanthanoid series which is well known to exhibit

+ 2

oxidation state.
(v) Complete the following equation

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} ⟶

Q. (a) Which metal in the first transition series (

3 d

series) exhibits

+ 1

oxidation state most frequently and why?
(b) Which of the following cations are coloured in aqueous solution and why?

S c^{3 +}, V^{3 +}, T i^{4 +}, M n^{2 +}

(

S c = 21, V = 23, T i = 22, M n = 25

Q. Of the following transition metals, the maximum numbers of oxidation states are exhibited by :

Q. Which metal in the first series of transition metals exhibits

+ 1

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Q. Name the oxometal anions of the first series of the transition metals in which the metal exhibits the oxidation state equal to its group number.

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