Question

Which of the following aqueous solutions will have maximum freezing point?

[Assume dilute solutions]

• A. $C_6{H}_{5}N{H}_{3}Cl$ solution having $0.01m$
• B. $Ca(N{O}_3{)}_2$ solution having $0.005m$
• C. $Al(N{O}_3{)}_3$ solution having $0.004m$
• D. Glucose solution having $0.04m$

Answer 1

Answer: (D)

Glucose solution having $0.04m$

Depression in freezing point of solution is colligative property, it depends upon the number of solute particles.

$C_6{H}_{5}N{H}_{3}Cl$ will give two ions

$\Rightarrow 2\times 0.01=0.02$

$Ca(N{O}_3{)}_2$ will give $3$ ions

$\Rightarrow 3\times 0.005=0.015$

$Al(N{O}_3{)}_3$ will give $4$ ions

$\Rightarrow 4\times 0.004=0.016$

Glucose will not dissociate but it will have maximum effective particle concentration, i.e. $0.04m$. So the answer is Option D.