Question

# Which of the following are correctly matched?ClF3→ Trigonal planar ICl−4→ Square planar I−3→ Linear ICl−2→ Linear

Solution

## The correct options are B ICl−4→ Square planar C I−3→ Linear D ICl−2→ Linear Lets take a common approach for these types of questions, i.e. calculate e.p., then get the geometry, place bond pairs and lone pairs and then after neglecting the lone pairs, get the shape. Lets calculate e.p. first, (i)ClF3→(V+L+A−C)2=(7+3)2 = 5 (By taking Cl as central atom; valence - 7) (ii)ICl−4→(V+L+A−C)2=(7+4+1)2 = 6 (By taking I as central atom; valence - 7) (iii)I−3→(V+L+A−C)2=(7+2+1)2 = 5 (By taking I as central atom; valence - 7) (iv)ICl−2→(V+L+A−C)2=(7+2+1)2 = 5 (By taking I as central atom; valence - 7) Now corresponding geometry for following compounds:- (i)ClF3→ Trigonal bipyramidal                    (ii)ICl−4→ Square bipyramidal (iii)I−3→ Trigonal bipyramidal                    (iv)ICl−2→ Trigonal bipyramidal →ClF3 will have 3 bp and 2lp. →ICl−4 will have 4bp and 2lp. →I−3 will have 2bp and 3lp. →ICl−2 will have 2bp ad 3lp. Now, shape of the compounds is: Now, we can see that → The shape of ClF3 is T-shape. → The shape of ICl−4 is square planar → The shape of I−3 is Linear → The shape of ICl−2 is Linear [* Note → Geometry & shape are different] [For shape, we don't consider lone pairs]

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