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Question

Which of the following are correctly matched?
  1. ClF3 Trigonal planar

  2. ICl4 Square planar

  3. I3 Linear

  4. ICl2 Linear


Solution

The correct options are
B

ICl4 Square planar


C

I3 Linear


D

ICl2 Linear


Lets take a common approach for these types of questions, i.e. calculate e.p., then get the geometry, place bond pairs and lone pairs and then after neglecting the lone pairs, get the shape.

Lets calculate e.p. first,

(i)ClF3(V+L+AC)2=(7+3)2 = 5

(By taking Cl as central atom; valence - 7)

(ii)ICl4(V+L+AC)2=(7+4+1)2 = 6

(By taking I as central atom; valence - 7)

(iii)I3(V+L+AC)2=(7+2+1)2 = 5

(By taking I as central atom; valence - 7)

(iv)ICl2(V+L+AC)2=(7+2+1)2 = 5

(By taking I as central atom; valence - 7)

Now corresponding geometry for following compounds:-

(i)ClF3 Trigonal bipyramidal                    (ii)ICl4 Square bipyramidal

(iii)I3 Trigonal bipyramidal                    (iv)ICl2 Trigonal bipyramidal

ClF3 will have 3 bp and 2lp.

ICl4 will have 4bp and 2lp.

I3 will have 2bp and 3lp.

ICl2 will have 2bp ad 3lp.

Now, shape of the compounds is:

Now, we can see that

The shape of ClF3 is T-shape.

The shape of ICl4 is square planar

The shape of I3 is Linear

The shape of ICl2 is Linear

[* Note Geometry & shape are different]

[For shape, we don't consider lone pairs]

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