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Question

Which of the following are equations for the plane passing through the points P(1,1,1),Q(3,0,2) and R(2,1,0)?

A
(2^i3^j+3^k)((x+2)^i+(y1)^j+z^k)=0
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B
x=3t,y=11t,z=23t
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C
(x+2)+11(y1)=3x
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D
(2^i^j+3^k)×(3^i+^k)((x+2)^i+(y1)^j+z^k)=0
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Solution

The correct option is B (2^i^j+3^k)×(3^i+^k)((x+2)^i+(y1)^j+z^k)=0
Given points are P(1,1,1),Q(3,0,2) and R(2,1,0)
Normal vector perpendicular to PQR is given by (QP)×Q=(2^i^j+3^k)×(3^i+2^k)
Therefore equation of plane PQR is,
(2^i^j+3^k)×(3^i+2^k)((x+2)^i+(y1)^j+z^k)=0

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