Which of the following compounds will give acetic acid with $K M n O_{4} / H / Δ$ :

C H_{3} - C H O

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C H_{3} - C H = C H - C H_{3}

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C H_{3} - C \equiv C - C H_{3}

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C H_{3} C H_{2} O H

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Solution

The correct options are
A $C H_{3} - C H O$
B $C H_{3} - C H = C H - C H_{3}$
C $C H_{3} - C \equiv C - C H_{3}$
D $C H_{3} C H_{2} O H$
Ethanol is oxidized to acetaldehyde on treatment with acidified potassium permanganate. Acetaldhyde is further oxidized to acetic acid.
Acidified potassium permanganate also breaks carbon carbon double bonds and triple bonds. Two carbons attached to multiple bond are oxidized to carboxylic group.
Thus the compounds of all the four options on oxidation with acidified potassium permanganate gives acetic acid.

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Similar questions

C H_{3} - O | | C - C H | C H_{3} - C H | C H O - C H | C H_{3} - C H_{3}

C H_{3} - C H | C H_{3} - C H_{2} - C H | C H_{3} - C H | C H_{3} - C H_{3}

C H_{3} - C H | C H_{3} - C H | C H_{3} - C H_{3}

I U P A C

In the reaction $C H_{3} - C H_{3} | C H - C H_{2} O - C H_{2} - C H_{3} + h e a t e d H I \to . . . . . . . . . .$

Which of the following compounds will be formed?

I U P A C

C H_{3} - C H = C H - C H = C H - C \equiv C - C H_{3}

C H_{3} M g X

C H_{3} - C \equiv C - H

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