Which of the following compounds will react faster?
$1$ -bromopropane or $2$ -bromo propane with $N a I$ in acetone.

1 - b r o m o p r o p a n e > 2 - b r o m o p r o p a n e

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1 - b r o m o p r o p a n e < 2 - b r o m o p r o p a n e

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1 - b r o m o p r o p a n e = 2 - b r o m o p r o p a n e

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None of these

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Solution

The correct option is A $1 - b r o m o p r o p a n e > 2 - b r o m o p r o p a n e$
Nucleophilic halide $B r$ is hindered in $2$ -bromopropane as compare to $1$ -bromopropane. Thus the reaction rate would be $1 -$ $b r o m o p r o p a n e$ $>$ $2 -$ $b r o m o p r o p a n e .$

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Which is the correct increasing order of boiling points of the following compounds?

1-bromoethane, 1-bromopropane , 1-bromobutane, Bromobenzene

(a) Bromobenzene < 1-bromobutane < 1-bromopropane < 1-bromoethane

(b) Bromobenzene < 1-bromoethane < 1-bromopropane < 1-bromobutane

(d) 1-bromoethane < 1-bromopropane < 1-bromobutane < Bromobenze

2 -

1 -

1 - b r o m o p r o p a n e

2 - b r o m o p r o p a n e

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