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Question

Which of the following contains maximum number of atoms?

A
0.16 g CH3
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B
0.28 g N2
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C
0.36 g C6H12O6
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D
1.1 g CO2
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Solution

The correct option is D 1.1 g CO2
No. of atoms in CH3 = Na×mole
= Na×0.1615

No. of atoms in N2 =Na×mole
=Na×0.2828

No. of atoms in C6H12O6=Na×0.36180

No. of atoms in CO2=Na×1.144
Hence 1.1 g of CO2 has the maximum no. of atoms.
Thus D is the correct option.

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