Which of the following equation is correct when ammonium hydroxide reacts with lead nitrate?

P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + 2 N H_{4} O H \to 2 N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓

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P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + N H_{4} O H \to 2 N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓

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P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + 2 N H_{4} O H \to N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓

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P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + 3 N H_{4} O H \to 2 N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓

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Solution

The correct option is A $P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + 2 N H_{4} O H \to 2 N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓$
$P b {(\begin{matrix} N O_{3} \end{matrix})}_{2} + 2 N H_{4} O H \to 2 N H_{4} N O_{3} + P b {(\begin{matrix} O H \end{matrix})}_{2} ↓$

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Similar questions

Identify the monoatomic and polyatomic ions from the following equation-
$P b (N O_{3})_{2}$ + $K_{2} S O_{4}$ $\to$ $2 K N O_{3}$ + $P b S O_{4}$

P b (O H)_{2}

6.7 \times 10^{- 6}

P b (O H)_{2}

p H = 8

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

lead reacts with oxygen. which ion should we take for lead? pb+1 or pb+2 or pb+4....

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