Byju's Answer
Standard XII
Chemistry
Heat of Formation
Which of the ...
Question
Which of the following expression is used to calculate the standard entropy change for the reaction:
A
Δ
r
S
0
=
[
2
S
0
F
e
+
S
0
A
l
2
O
3
]
−
[
2
S
0
A
l
+
S
0
F
e
2
O
3
]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Δ
r
S
0
=
S
0
A
l
2
O
3
−
S
0
F
e
2
O
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Δ
r
S
0
=
[
2
S
0
F
e
+
S
0
F
e
2
O
3
]
−
S
0
F
e
2
O
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Δ
r
S
0
=
[
S
0
F
e
+
1
2
S
0
F
e
2
O
3
]
−
[
S
0
A
l
+
S
0
F
e
2
O
3
]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
Δ
r
S
0
=
[
2
S
0
F
e
+
S
0
A
l
2
O
3
]
−
[
2
S
0
A
l
+
S
0
F
e
2
O
3
]
The balanced chemical reaction is:
2
A
l
(
s
)
+
F
e
2
O
3
(
s
)
→
2
F
e
(
s
)
+
A
l
2
O
3
(
s
)
Δ
H
∘
=
−
851.4
k
J
The expression is used to calculate the standard entropy change for the reaction is:
Δ
r
S
0
=
[
2
S
0
F
e
+
S
0
A
l
2
O
3
]
−
[
2
S
0
A
l
+
S
0
F
e
2
O
3
]
The standard entropy change for the reaction is the difference in the total standard entropy of products and the total standard entropy of reactants.
Hence, the correct option is
A
Suggest Corrections
0
Similar questions
Q.
Standad Gibbs energy of the reaction,
Δ
r
G
o
at a certain temperature can be computed as
Δ
r
G
o
=
Δ
r
H
o
−
T
Δ
r
S
o
and the change in the value of
Δ
r
H
o
and
Δ
r
S
o
for a reaction with temperature can be copmuted as follows :
Δ
r
H
o
T
2
−
Δ
r
H
o
T
1
=
Δ
r
C
o
p
(
T
2
−
T
1
)
Δ
r
S
o
T
2
−
Δ
r
S
o
T
1
=
Δ
r
C
o
p
l
n
T
2
T
1
Δ
r
G
o
=
Δ
r
H
o
−
T
Δ
r
S
o
and by
Δ
r
G
o
=
−
R
T
l
n
K
e
q
Consider the following reaction,
C
O
(
g
)
+
2
H
2
(
g
)
⇌
C
H
3
O
H
(
g
)
Given :
Δ
f
H
o
(
C
H
3
O
H
(
g
)
)
=
−
201
kJ mol
−
1
Δ
f
H
o
(
C
O
(
g
)
)
=
−
114
kJ mol
−
1
S
o
(
C
H
3
O
H
(
g
)
)
=
240
kJ mol
−
1
S
o
(
H
2
(
g
)
)
=
29
J K
−
1
mol
−
1
S
o
(
C
O
(
g
)
)
=
198
J mol
−
1
K
−
1
C
o
p
,
m
(
H
2
)
=
28.8
J/mol-K
C
o
p
,
m
(
C
O
)
=
29.4
J/mol-K
C
o
p
,
m
(
C
H
3
O
H
)
=
44
J/mol-K
and
l
n
(
320
300
)
=
0.06
All data were taken at
300
K
.
The
Δ
r
G
o
(
in kJ/mol
)
at
320
K
is
−
x
. Find the value of
x
. (Report the answer to the closest integer)
Q.
Calculate the standard enthalpy change for the a cell reaction which has a standard cell potential of
1.50
V
. The cell reaction involves the transfer of 2 moles of electrons and standard entropy change is
110
J
K
−
1
.
Q.
The equilibrium constant for the reaction given below is
2.0
×
10
−
7
at 300 K. Calculate the standard free energy change for the reaction;
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
Also, calculate the standard entropy change if
△
H
o
=
28.40
k
J
m
o
l
−
1
.
Q.
Calculate the entropy change for the following reaction:
C
a
C
O
3
(
s
)
⟶
C
a
O
(
s
)
+
C
O
2
(
g
)
S
o
(
J
K
−
1
m
o
l
−
1
)
92.9
39.7
213.6
Q.
The standard potential of a cell using the reaction
2
N
i
(
s
)
+
O
2
+
2
H
2
O
⇌
2
N
i
(
O
H
)
2
is 1.12.The heat of the reaction is
−
504.2
K
j
m
o
l
−
1
at
25
∘
C
. Calculate the entropy change.
View More
Related Videos
Thermochemistry
CHEMISTRY
Watch in App
Explore more
Heat of Formation
Standard XII Chemistry
Solve
Textbooks
Question Papers
Install app