You visited us 1 times! Enjoying our articles? Unlock Full Access!

Enthalpy of Solution

Which of the ...

Question

Which of the following expression is used to calculate the standard entropy change for the reaction:

Δ_{r} S^{0} = [2 S_{F e}^{0} + S_{A l_{2} O_{3}}^{0}] - [2 S_{A l}^{0} + S_{F e_{2} O_{3}}^{0}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Δ_{r} S^{0} = S_{A l_{2} O_{3}}^{0} - S_{F e_{2} O_{3}}^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ_{r} S^{0} = [2 S_{F e}^{0} + S_{F e_{2} O_{3}}^{0}] - S_{F e_{2} O_{3}}^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ_{r} S^{0} = [S_{F e}^{0} + \frac{1}{2} S_{F e_{2} O_{3}}^{0}] - [S_{A l}^{0} + S_{F e_{2} O_{3}}^{0}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $Δ_{r} S^{0} = [2 S_{F e}^{0} + S_{A l_{2} O_{3}}^{0}] - [2 S_{A l}^{0} + S_{F e_{2} O_{3}}^{0}]$
The balanced chemical reaction is:

$2 A l (s) + F e_{2} O_{3} (s) \to 2 F e (s) + A l_{2} O_{3} (s)$ $Δ H^{\circ} = - 851.4 k J$
The expression is used to calculate the standard entropy change for the reaction is:

$Δ_{r} S^{0} = [2 S_{F e}^{0} + S_{A l_{2} O_{3}}^{0}] - [2 S_{A l}^{0} + S_{F e_{2} O_{3}}^{0}]$
The standard entropy change for the reaction is the difference in the total standard entropy of products and the total standard entropy of reactants.

Hence, the correct option is $A$

Suggest Corrections

Similar questions

Δ_{r} G^{o}

Δ_{r} G^{o} = Δ_{r} H^{o} - T Δ_{r} S^{o}

Δ_{r} H^{o}

Δ_{r} S^{o}

Δ_{r} H_{T_{2}}^{o} - Δ_{r} H_{T_{1}}^{o} = Δ_{r} C_{p}^{o} (T_{2} - T_{1})

Δ_{r} S_{T_{2}}^{o} - Δ_{r} S_{T_{1}}^{o} = Δ_{r} C_{p}^{o} l n \frac{T_{2}}{T_{1}}

Δ_{r} G^{o} = Δ_{r} H^{o} - T Δ_{r} S^{o}

Δ_{r} G^{o} = - R T l n K_{e q}

C O (g) + 2 H_{2} (g) ⇌ C H_{3} O H (g)

Δ_{f} H^{o} (C H_{3} O H (g)) = - 201 {kJ mol}^{- 1}

Δ_{f} H^{o} (C O (g)) = - 114 {kJ mol}^{- 1}

S^{o} (C H_{3} O H (g)) = 240 {kJ mol}^{- 1}

S^{o} (H_{2} (g)) = 29 {J K}^{- 1} {mol}^{- 1}

S^{o} (C O (g)) = 198 {J mol}^{- 1} K^{- 1}

C_{p, m}^{o} (H_{2}) = 28.8 J/mol-K

C_{p, m}^{o} (C O) = 29.4 J/mol-K

C_{p, m}^{o} (C H_{3} O H) = 44 J/mol-K

l n (\frac{320}{300}) = 0.06

300 K

Δ_{r} G^{o} (in kJ/mol)

320 K

- x

x

1.50 V

110 J K^{- 1}

2.0 \times 10^{- 7}

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

△ H^{o} = 28.40 k J m o l^{- 1} .

C a {C O}_{3} (s) ⟶ C a O (s) + C O_{2} (g)

S^{o} (J K^{- 1} m o l^{- 1})

92.9

39.7

213.6

2 N i (s) + O_{2} + 2 H_{2} O ⇌ 2 N i {(O H)}_{2}

- 504.2 K j {m o l}^{- 1}

25^{\circ} C

Join BYJU'S Learning Program