Question

Which of the following graphs is correct for a zero order reaction?

• A.
• B.
• C.
• D.

Answer 1

Answer: (A), (D)

The correct options are
A

D

For zero order reaction,

rate $=\frac{-d\left[A\right]}{dt}=k$

With time, rate remains constant until the reactant is consumed, then the rate falls to zero nearly as there is no more reactant left!

On integrating, we get

$\int \frac{d\left[A\right]}{dt}=-\int kdt$

[A] = –kt + C . . . .(i)

when, t = 0, [A] = $[A{]}_0$

$\therefore$ On putting the value of ‘C’ in Eq. (i)

[A] = –kt + $[A{]}_0$

$\therefore$ A graph of [A] Vs t is a straight line with slope = – k

Here, [A] = concentration of reactant.

Thus, graph (a) and (d) are correct.