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Question

Which of the following has been arranged in order of increasing oxidation number of nitrogen?


A
NH3<N2O5<NO<N2
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B
NO+2<NO3<NO2<N3
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C
NH+4<N2H4<NH2OH<N2O
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D
NO2<NaN3<NH+4<N2O
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Solution

The correct option is C $$NH^+_4 < N_2H_4 < NH_2OH < N_2O$$
Oxidation state of $$H$$ $$=+1$$
Oxidation state of $$O$$ $$=-2$$
For option A oxidation state of $$N$$ in $$NH_3$$ is -3,in $$N_2O_5$$ is +5,in $$NO$$ is +2. So this is not increasing order of oxidation state of nitrogen.
For option B oxidation state of $$N$$ in $$NO_2^{+}$$ is +5,in $$NO_3^{-}$$ is +5. So this is not increasing order of oxidation state of nitrogen.
For option C oxidation state of $$N$$ in $$NH_4^{+}$$ is -3,in $$N_2H_4$$ is -2,in $$NH_2OH$$ is -1 and in $$N_2O$$ is +1. So this is correct answer as compounds are arranged in increasing order of oxidation number of nitrogen.
For option A oxidation state of $$N$$ in $$NO_2$$ is -4,in $$NaN_3$$ is -1/3,in $$NH_4^{+}$$ is -3. So this is not increasing order of oxidation state of nitrogen.

Chemistry

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