Which of the following hydrocarbons cannot be obtained by Sabatier and Senderen's reaction

$C H_{4}$

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$C_{2} H_{6}$

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$C_{3} H_{8}$

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All

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Solution

The correct option is A
$C H_{4}$

Methane can not be obtained by Sabatier and Sendern's reaction because in this the product obtained contain minimum two carbon atoms.

$C H_{2} = C H_{2} + H_{2} N i \to C H_{3} - C H_{3} C H \equiv C H + 2 H_{2} N i \to C H_{3} - C H_{3}$

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