Question

Which of the following ion has the maxium magnetic moment?

• A. $M{n}^{3+}$
• B. $C{u}^{2+}$
• C. $F{e}^{3+}$
• D. $V^{3+}$

Answer 1

The correct option is C $F{e}^{3+}$

$M{n}^{3+}⟶4s^{0}3d^4$ number of unpaired $e^{-}=4$

$C{u}^{2+}⟶4s^{0}3d^9$ number of unpaired $e^{-}=1$

$F{e}^{3+}⟶4s^{0}3d^5$ number of unpaired $e^{-}=5$

$V^{3+}⟶4s^{0}3d^2$ number of unpaired $e^{-}=2$

More is the number of unpaired $e^{-}$ higher is the magnetic moment.

$M_{F{e}^{3+}}=\sqrt{5(5+2)}$

$=\sqrt{35}=5.91$ BM.