Question

# Which of the following ion has the maxium magnetic moment?

A
Mn3+
B
Cu2+
C
Fe3+
D
V3+

Solution

## The correct option is C $$Fe^{3+}$$$$Mn^{3+}\longrightarrow 4s^03d^4$$ number of unpaired $$e^-=4$$$$Cu^{2+}\longrightarrow 4s^03d^9$$ number of unpaired $$e^-=1$$$$Fe^{3+}\longrightarrow 4s^03d^5$$ number of unpaired $$e^-=5$$$$V^{3+}\longrightarrow 4s^03d^2$$ number of unpaired $$e^-=2$$More is the number of unpaired $$e^-$$ higher is the magnetic moment.$$M_{Fe^{3+}}=\sqrt{5(5+2)}$$$$=\sqrt {35}=5.91$$ BM.Chemistry

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