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Question

Which of the following ion has the maxium magnetic moment?


A
Mn3+
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B
Cu2+
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C
Fe3+
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D
V3+
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Solution

The correct option is C $$Fe^{3+}$$
$$Mn^{3+}\longrightarrow 4s^03d^4$$ number of unpaired $$e^-=4$$
$$Cu^{2+}\longrightarrow 4s^03d^9$$ number of unpaired $$e^-=1$$
$$Fe^{3+}\longrightarrow 4s^03d^5$$ number of unpaired $$e^-=5$$
$$V^{3+}\longrightarrow 4s^03d^2$$ number of unpaired $$e^-=2$$
More is the number of unpaired $$e^-$$ higher is the magnetic moment.
$$M_{Fe^{3+}}=\sqrt{5(5+2)}$$
$$=\sqrt {35}=5.91$$ BM.

Chemistry

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