Which of the following is a redox reaction?

2 C r O_{4}^{2 -} + 2 H^{+} \to C r_{2} O_{7}^{2 -} + H_{2} O

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C u S O_{4} + 4 N H_{3} \to [C u (N H_{3})_{4}] S O_{4}

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N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + N a I

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C r_{2} O_{7}^{2 -} + 2 O H^{-} \to 2 C r O_{4}^{2 -} + H_{2} O

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Solution

The correct option is D $N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + N a I$
Option A: Dehydration reaction is occurring and hence no change in oxidation
Option B: Complexation of Cu with $N H_{3}$ . So no change in oxidation.
Option D: Hydration of $C r_{2} O_{7}^{2 -}$ is occurring here. So no change in oxidation
Option C: $I_{2}$ reduces to $I^{-}$ . This is a redox reaction as there is a change in oxidation state of $I_{2}$ . This is the correct answer

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C r_{2} O_{7}^{2 -} + H_{2} O \to 2 C r O_{4}^{2 -} + 2 H^{+}

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2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

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