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Introduction to Alkanes

Which of the ...

Question

Which of the following is a stable free radical?

$C H_{2} = C H - ∙ C H_{2}$

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$(C H_{3})_{2} ∙ C H$

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$C H_{3} ∙ C H_{2}$

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$(C H_{3})_{3} C^{∙}$

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Solution

The correct option is A
$C H_{2} = C H - ∙ C H_{2}$

Radical stability increases in the order methyl < primary < secondary < tertiary. But due to resonance stabilization, the allyl radical is the most stable one:

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Similar questions

C H_{3} O \oplus C H_{2}

C H_{3} \oplus C H_{2}

{M e}_{2} \oplus C H

C H_{3} C H_{2} \oplus C H_{2}

C H_{2} = C H - \oplus C H_{2}

C H_{3} C H_{2} \oplus C H_{2}

C H_{2} = \oplus C H

C H_{3} \oplus C H_{2}

C H_{2} = C H - + C H_{2} and C H_{2} = C H - C H_{2} - + C H_{2}

C H_{3} - N H - + C H_{2} and + C H_{2} - O H

C H_{3} - O - C H_{2} - + C H_{2} and C H_{2} - O - + C H_{2}

C H_{3} - + C H - C H_{2} C H_{2} C H_{3} and C H_{3} C H_{2} - + C H - C H_{2} C H_{3}

C H_{3} - C H (C H_{3}) - C H (C H_{3}) - C H = C H - C H_{2} - C H O

C H_{2} = C H - C H = C H - + C H_{2}

C H_{2} = C H - + C H - C H = C H_{2}

C H_{2} = C H - + C H - - C H - + C H_{2}

+ C H_{2} - C H = C H - - C H - + C H_{2}

C H_{2} = C H - C H_{3} - C H (C H_{3}) - C H_{3}

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