Which of the following is a unit vector along 3i−2j ?
A
−3√5i+2√5j
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B
3√13i+2√13j
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C
−3√5i−2√5j
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D
3√13i−2√13j
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Solution
The correct option is D3√13i−2√13j Given: 3i−2j
A unit vector along any vector can be found out by dividing the vector with the magnitude of the vector. ⇒3i−2j√32+(−2)2=3i−2j√13 ⇒3√13i−2√13j