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Question

Which of the following is/are correct for the function xcosyx?

A
Not homogenous
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B
Homogenous
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C
Degree =1
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D
Degree=2
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Solution

The correct options are
B Homogenous
C Degree =1
Let the given function be f(x,y)=xcos(yx)
Now, f(kx,ky)=kxcos(kykx)
f(kx,ky)=kxcos(kykx)=kxcos(yx)=kf(x,y)
the function is homogeous as k>0 and is of degree 1.

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