Question

Which of the following is correct for the orbitals of Cr?

• A.
• B.
• C.
• D.

Answer 1

Answer: (B), (C)

The correct options are
B

C

same as previous

$C{r}_{24}$ = [Ar] 3$d^5$ 4$s^1$

Both are corrected,because spin can be both ($\pm$ $\frac{1}{2}$)