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Hydrides of Nitrogen

Which of the ...

Question

Which of the following is not correct?

Hydrolysis of

N C l_{3}

gives

N H_{3}

and HOCl

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N H_{3}

is less stable than

P H_{3}

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N H_{3}

is a weak reducing reagent compared to

P H_{3}

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Nitric oxide in solid state exhibits diamagnetic property.

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Solution

The correct option is D $N H_{3}$ is less stable than $P H_{3}$
Bond energy in nitrogen hydride is more than in phosphorous hydride. So, ammonia is more stable than phosphorous hydride.

Hydrolysis of $N {C l}_{3}$ gives ammonia.

$N {C l}_{3} + 3 H_{2} O ⟶ N H_{3} + 3 H O C l$

Nitric oxide $N O$ exhibits diamagnetic property because of dimerisation.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(1) N H_{3} > P H_{3} > N F_{3} (2) N F_{3} > N H_{3} > P H_{3}

(3) N H_{3} > N F_{3} > P H_{3} (4) P H_{3} > N H_{3} > N F_{3}

N C l_{3}

N H_{3}

The increasing order of enthalpy of vaporization of NH₃, PH₃, and AsH₃ is

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

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