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Question

Which of the following is the sketch of the graph y = (|cosx|cosx)


A

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B

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C

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D

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Solution

The correct option is D


y = |cosx|cosx

Here, y = {1;cosx > 01;cosx < 0

Graph of y=cosx

we can observe from the graph

cosx is positive when

2nππ2< x<2nπ+π2

cosx is nagative when

2nπ+π2< x<2nπ+3π2

y = {12nπ π2 < x < 2nπ + π212nπ + π2 < x < 2nπ + 3π2

when cosx = 0,y = |cosx|cosx is not defined.

so,it should be plotted as:


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