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Question

Which of the following numbers are perfect cubes? In case of perfect cube find the number with cube is the given number.
$$21952$$


Solution

We have,

$$\displaystyle \sqrt[3]{21952}=\sqrt[3]{2\times2\times2\times2\times2\times2\times7\times7\times7}$$

This is perfect cube.


Hence, this is the answer.

Mathematics

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