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Question

Which of the following reactions are spontaneous?
(a) Pb4++Sn2+Sn4++Pb2+


(b) Sn4++Pb2+Pb4++Sn2+

(EoPb4+/Pb2+=1.69 V,EoSn4+/Sn2+=0.15 V)

A
Only (a)
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B
Only (b)
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C
Both (a) and (b)
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D
Neither (a) nor (b)
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Solution

The correct option is C Only (a)
We know that Eocell=EocathodeEoanode
Eo
Also, Sn2+Sn4++2e 0.15V
Pb4++2ePb2+ 1.69V
__________________________
Pb4++Sn2+Sn4++Pb2+ Eocell=1.690.15=+1.54V
___________________________

Eo
Also, Pb2+Pb4++2e 1.69V
Sn4++2eSn2+ 0.15V
__________________________
Sn4++Pb2+Pb4++Sn2+ Eocell=0.151.69=1.54V
___________________________

For spontaneous rection ΔG<0
(a) ΔG=nFEocell=2×F×1.54ΔG<0spontaneous
(a) ΔG=nFEocell=2×F×(1.54)ΔG>0nonspontaneous

Option A is the correct answer.

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