Question

Which of the following reactions is/are correct when $C{l}_2$ reacts with $N{H}_3$?

• A. $N{H}_3+C{l}_2\to NC{l}_3+HCl$
  $Excess$
  
• B. $N{H}_3+C{l}_2\to N_2+N{H}_{4}Cl$
  $Excess$
• C. $N{H}_3+C{l}_2\to N_2+N{H}_{4}Cl$
  $Excess$
• D. $N{H}_3+C{l}_2\to NC{l}_3+HCl$
  $Excess$

Answer 1

Answer: (B), (D)

The correct options are
B $N{H}_3+C{l}_2\to N_2+N{H}_{4}Cl$
$Excess$
D $N{H}_3+C{l}_2\to NC{l}_3+HCl$

$Excess$
$N{H}_3\left(excess\right)+C{l}_2\to N_2+N{H}_{4}Cl$

$N{H}_3+C{l}_2\left(excess\right)\to NC{l}_3+HCl$