Which of the following reactions will give $2, 2$ -dibromopropane as its product?

C H \equiv C H + 2 H B r \to

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C H_{3} - C H = C H_{2} + H B r \to

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C H_{3} - C \equiv C H + 2 H B r \to

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C H_{3} C H = C H B r + 2 H B r \to

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Solution

The correct option is C $C H_{3} - C \equiv C H + 2 H B r \to$

Set wise preparalion of $2, 2$ dibromo propane takes place according to Markownikoff's rule using butyne and hydrogen bromide.

Mechanism:
step 1 :

Step 2 :

Option: $C$

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Similar questions

C H_{3} - C H = C H_{2} + H B r \to

-------- the product is

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

Q. Which will undergo reaction with ammonical

A g N O_{3}

Which are free radical reactions

C H_{3} - C H | C H_{3} - C H = C H_{2} + H B r

product which is Prodominate :

X

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Which of the following reactions will give 2,2-dibromopropane as its product?

The correct option is C CH3−C≡CH+2HBr→Set wise preparalion of 2,2 dibromo propane takes place according to Markownikoff's rule using butyne and hydrogen bromide.Mechanism:step 1 :Step 2 :Option: C

Which of the following reactions will give $2, 2$ -dibromopropane as its product?

The correct option is C $C H_{3} - C \equiv C H + 2 H B r \to$

Set wise preparalion of $2, 2$ dibromo propane takes place according to Markownikoff's rule using butyne and hydrogen bromide.

Mechanism:
step 1 :

Step 2 :

Option: $C$