1
Question
Which of the following representation of atomic model is incorrect with respect to Bohr-Bury scheme?
(I)
(II)
(III)
Explain giving reasons.
[3 Marks]
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| (I) | (II) | (III) |
Explain giving reasons.
[3 Marks]
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Solution
According to Bohr-Bury scheme, the maximum number of electrons present in a shell is given by the formula 2n2, where ‘n’ is the orbit number.
Therefore, the K shell (n=1) will have a maximum of 2 electrons and the L shell (n=2) will have a maximum of 8 electrons.
In representation (I), K-shell has 2 electrons and L-shell has 5 electrons.
So, it is a correct representation with respect to Bohr-Bury scheme.
[1 Mark]
In representation (II), K-shell has 4 electrons and L-shell has 8 electrons.
So, it is an incorrect representation with respect to Bohr-Bury scheme, since K-shell cannot have 4 electrons.
[1 Mark]
In representation (III), K-shell has 2 electrons and L-shell has 7 electrons.
So, it is a correct representation with respect to Bohr-Bury scheme.
[1 Mark]
Therefore, the K shell (n=1) will have a maximum of 2 electrons and the L shell (n=2) will have a maximum of 8 electrons.
In representation (I), K-shell has 2 electrons and L-shell has 5 electrons.
So, it is a correct representation with respect to Bohr-Bury scheme.
[1 Mark]
In representation (II), K-shell has 4 electrons and L-shell has 8 electrons.
So, it is an incorrect representation with respect to Bohr-Bury scheme, since K-shell cannot have 4 electrons.
[1 Mark]
In representation (III), K-shell has 2 electrons and L-shell has 7 electrons.
So, it is a correct representation with respect to Bohr-Bury scheme.
[1 Mark]
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