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Which of the ...

Question

Which of the following represents the correct reaction?

{NADP}^{+} + 2 H^{+} + e^{-} FNR - - \to

NADPH + H^{+}

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{NADP}^{+} + H^{+} + 2 e^{-} FNR - - \to

NADPH + H^{+}

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{NADP}^{+} + 2 H^{+} + 2 e^{-} FNR - - \to

NADPH + H^{+}

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{NADP}^{+} + H^{+} + e^{-} FNR - - \to

NADPH + H^{+}

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Solution

The correct option is C ${NADP}^{+} + 2 H^{+} + 2 e^{-} FNR - - \to$ $NADPH + H^{+}$
Ferredoxin- ${NADP}^{+}$ -reductase (FNR) is an enzyme complex which catalyses the reaction of reduction of ${NADP}^{+}$ . It is found in the stroma of the thylakoid. The reaction catalysed is as follows
${NADP}^{+} + 2 H^{+} + 2 e^{-} FNR - - \to$ $NADPH + H^{+}$

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Similar questions

C_{3}

C O_{2}

H_{2} O_{2} \to O_{2} + 2 H^{\oplus} + 2 e^{-}

E^{⊖} = - 0.69 V

H_{2} O_{2} + 2 H^{\oplus} + 2 e^{-} \to 2 H_{2} O

E^{⊖} = 1.77 V

I^{⊖} \to + 2 e^{-}

E^{⊖} = - 0.535 V

N A D P^{+}

N A D P H + H^{+}

Given :

Oxidation :

$H_{2} O_{2} \to O_{2} + 2 H^{\oplus} + 2 e^{-}$

$E^{⊖} = - 0.69 V$ ;

$2 F^{⊖} \to F_{2} + 2 e^{-}$

$E^{⊖} = - 2.87 V$ ;

Reduction :

$H_{2} O_{2} + 2 H^{\oplus} + 2 e^{-} \to 2 H_{2} O$

$E^{⊖} = - 1.77 V$ ;

$2 I^{⊖} \to I_{2} + 2 e^{-}$ $E^{⊖} = - 0.54 V$ ;

Which of the following statements is/are correct ?

The reaction in which ATP and $N A D P H_{2}$ is produced is called

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