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Question

Which of the following samples will have same number of atoms as $$6.4$$g of $$CH_4$$?


A
8.5g of NH3
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B
12g of H2O
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C
32g of SO2
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D
22g of CO2
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Solution

The correct options are
A $$8.5g$$ of $$NH_3$$
B $$12g$$ of $$H_2O$$
Number atoms of $$6.4$$ gm of $${ CH }_{ 4 }=\dfrac { 5\times 6.4 }{ 16 } \times 6.023\times { 10 }^{ 23 }$$
                                                         $$=2.0\times 6.023\times { 10 }^{ 23 }$$
A) Number atoms of $${ NH }_{ 3 }=4\times \dfrac { 8.5 }{ 17 } \times 6.023\times { 10 }^{ 23 }$$
                                                         $$=2\times 6.023\times { 10 }^{ 23 }$$
B) Number atoms of $$12$$ gm of $${ H }_{ 2 }O=\dfrac { 3\times 12 }{ 18 } \times 6.023\times { 10 }^{ 23 }$$
                                                            $$=2\times 6.023\times { 10 }^{ 23 }$$
C) Number of atoms of $$32$$ gm of $${ SO }_{ 2 }=\dfrac { 3\times 32 }{ 64 } \times 6.023\times { 10 }^{ 23 }$$
                                                                $$=1.5\times 6.023\times { 10 }^{ 23 }$$
D) Number of atoms of $$22$$ gm of $${ CO }_{ 2 }=\dfrac { 3\times 22 }{ 44 } \times 6.023\times { 10 }^{ 23 }$$
                                                                 $$=1.5\times 6.023\times { 10 }^{ 23 }$$
$$\therefore$$   Correct answer are $$A$$ and $$B$$.

Chemistry

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