Which of the following sequences is correct for decreasing order of ionic radius?
A
Se2−>I−>Br−>O2−>F−
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B
I−>Se2−>O2−>Br−>F−
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C
Se2−>I−>Br−>F−>O2−
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D
I−>Se2−>Br−>O2−>F−
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Solution
The correct option is DI−>Se2−>Br−>O2−>F−
The size increases with increasing number of shells, irrespective of the charge. And if number of shells are same, more negative ion is larger. Thus correct order is