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Question

Which of the following sets of quantum numbers represents the highest energy of an atom?


A
n=3,l=0,m=0,s=+1/2
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B
n=3,l=1,m=1,s=+1/2
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C
n=4,l=2,m=1,s=+1/2
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D
n=4,l=0,m=0,s=+1/2
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Solution

The correct option is C $$n = 4, l = 2, m = 1, s = +1/2$$
The sets of the quantum numbers and the corresponding orbitals are as shown below.
$$a) n=3,l=0$$ means $$3s-$$ orbital
$$b) n=3,l=1$$ means $$3p-$$ orbital
$$c) n=4,l=2$$ means $$4d-$$ orbital
$$d) n=4,l=0$$ means $$4s-$$ orbital
Increasing order of energy among three orbitals is $$3s<3p<4s<4d$$
$$\therefore 4d$$ has highest energy.
Hence, the set c of quantum numbers ($$n = 4, l = 2, m = 1, s = +1/2$$)  represents the highest energy of an atom.

Chemistry

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