Which of the following shows positive deviation from Raoult's law?

C_{6} H_{6}

and

C_{6} H_{5} C H_{3}

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C_{6} H_{6}

and

C C l_{4}

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C H C l_{3}

and

C_{2} H_{5} O H

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C H C_{3}

and

C H_{3} C O C H_{3}

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Solution

The correct option is A $C_{6} H_{6}$ and $C_{6} H_{5} C H_{3}$
Option A is the correct answer.
Positive Deviation from Raoult's law occurs when the vapour pressure of the component is greater than what is expected in Raoult's law.
Benzene has slightly weaker intermolecular forces than methylbenzene and as such will form a vapour more readily and has a lower boiling point.

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Similar questions

Column - I	Column - II
a) A nearly ideal solution	p) $H_{2} O + C_{2} H_{5} O H$
b) A solution showing positive deviation	q) $C_{6} H_{6} + C_{6} H_{5} C H_{3}$
c) A solution showing negative deviation	r) $C_{6} H_{6} + C H C l_{3}$
d) An azeotropic mixture	s) $C H_{3} C O C H_{3}$ + $C_{2} H_{5} O H$
	t) $Δ H$ and $Δ V$ are positive
	u) $Δ H$ and $Δ V$ are negative

C_{2} H_{5} O H

C H C l_{3}

C H C l_{3} + C H_{3} C O C H_{3}

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