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Standard XII

Chemistry

Idea of Hybridisation

Which of the ...

Question

Which of the following species (A), (B), (C) and (D) has $s p^{2}$ hybridized carbon?
$C H {_{3}}^{+}$ , $C H {_{3}}^{-}$ , $∙ C H_{3}$ , : $C H_{2}$

A only

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A and B only

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A and C only

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A, C and D

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Solution

The correct option is C A, C and D
$C H {_{3}}^{+}$ , $∙ C H_{3}$ , : $C H_{2}$ have $s p^{2}$ hybridized carbon because in $C H {_{3}}^{+}$ , $∙ C H_{3}$ , $3$ bond pair and zero lone pair and in : $C H_{2}$ , $2$ bond pair and $1$ lone pair.
$C H {_{3}}^{-}$ has $s p^{3}$ hybridized carbon.

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Similar questions

Which hybrid orbitals are used by carbon atoms in the following molecules?

CH₃–CH₃; (b) CH₃–CH=CH₂; (c) CH₃-CH₂-OH; (d) CH₃-CHO (e) CH₃COOH

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. In the given compound A,C and A,D are exbhits which of the following isomerism :

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} N H_{2}

Butanamine

(1^{o})

(b)

C H_{3} - C H_{2} - N H_{2} | C H - C H_{3}

Butan-2-amine

(1^{o})

(c)

C H_{3} - C H_{3} | C H - C H_{2} - N H_{2}

2-Methylpropanamine

(1^{o})

(d)

C H_{3} - C H_{3} | C | - C H_{3} N H_{2}

2-methylpropan-2-amine

(1^{o})

(e)

C H_{3} - C H_{2} - C H_{2} - N H - C H_{3}

N-methylpropanamine

(2^{o})

Q. In the given example B,C and B,D are :

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} N H_{2}

Butanamine

(1^{o})

(b)

C H_{3} - C H_{2} - N H_{2} | C H - C H_{3}

Butan-2-amine

(1^{o})

(c)

C H_{3} - C H_{3} | C H - C H_{2} - N H_{2}

2-Methylpropanamine

(1^{o})

(d)

C H_{3} - C H_{3} | C | - C H_{3} N H_{2}

2-methylpropan-2-amine

(1^{o})

(e)

C H_{3} - C H_{2} - C H_{2} - N H - C H_{3}

N-methylpropanamine

(2^{o})

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

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Which of the following species (A), (B), (C) and (D) has sp2 hybridized carbon?CH3+, CH3−, ∙CH3, :CH2

The correct option is C A, C and DCH3+, ∙CH3, :CH2 have sp2 hybridized carbon because in CH3+, ∙CH3, 3 bond pair and zero lone pair and in :CH2, 2 bond pair and 1 lone pair.CH3− has sp3 hybridized carbon.

Which of the following species (A), (B), (C) and (D) has $s p^{2}$ hybridized carbon?
$C H {_{3}}^{+}$ , $C H {_{3}}^{-}$ , $∙ C H_{3}$ , : $C H_{2}$

The correct option is C A, C and D
$C H {_{3}}^{+}$ , $∙ C H_{3}$ , : $C H_{2}$ have $s p^{2}$ hybridized carbon because in $C H {_{3}}^{+}$ , $∙ C H_{3}$ , $3$ bond pair and zero lone pair and in : $C H_{2}$ , $2$ bond pair and $1$ lone pair.
$C H {_{3}}^{-}$ has $s p^{3}$ hybridized carbon.