Question

Which of the following species does not use $d_{z^2}$ orbitals in hybridisation?

• A. $Cl{F}_3$
• B. $Br{F}_5$
• C. $\left[Ni\right(CN{)}_4{]}^{2-}$
• D. $Xe{F}_2$

Answer 1

The correct option is C $\left[Ni\right(CN{)}_4{]}^{2-}$

$Cl{F}_3$ is $s{p}^{3}d$ hybridised using $d_{z^2}$ orbital.

$Br{F}_5$ is $s{p}^3{d}^2$ hybridised using $d_{z^2}$ and $d_{x^2-y^2}$ orbitals.

$\left[Ni\right(CN{)}_4{]}^{2-}$ is $ds{p}^2$ hybridised using $d_{x^2-y^2}$ orbital.

$Xe{F}_2$ is $s{p}^{3}d$ hybridised using $d_{z^2}$ orbital.