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Question

Which of the following statements about the composition of the vapour over an ideal $$1:1$$ molar mixture of benzene and toluene is correct? Assume that the temperature is constant $$25^{\circ}C$$. (Given Vapour Pressure Data at $$25^{\circ}C$$, benzene $$= 12.8\ kPa,$$ toluene $$= 3.85\ kPa$$)


A
The vapour will contain a higher percentage of benzene
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B
The vapour will contain a higher percentage of toulene
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C
The vapour will contain a equal amount of benzene and toulene
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D
Not enough information is given to make a prediction
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Solution

The correct option is A The vapour will contain a higher percentage of benzene
$$A\rightarrow benzene, B\rightarrow toluene$$

In $$1 : 1$$ molar mixture of $$ A$$ and $$B$$

$$\therefore X_A = \frac {1}{2}, X_B= \frac {1}{2}$$

$$P = P_A^oX_A+ P_B^oX_B$$

$$P= 12.8 \times \frac {1}{2}+ 3.85 \times \frac {1}{2}= 8.325\ kPa$$

$$Y_A= \dfrac {P_A^oX_A}{P} =\dfrac{ 12.8\times \frac {1}{2}}{8.325} =0.768$$

$$\Rightarrow Y_B =1-Y_A = 1.0.768 = 0.232$$

So the vapour will contain higher percentage of benzene. 

Option A is correct.

Chemistry

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