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Question

Which one are correct about the solution that contains 3.42 ppm Al2(SO4)3 and 1.42 ppm Na2SO4
 


A
[Al3+]=[Na+]
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B
[SO24]=[Na+]=[Al3+]
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C
[SO24]=[Na+]+[Al3+]
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D
[SO24]=[Na+]
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Solution

The correct options are
A [Al3+]=[Na+]
C [SO24]=[Na+]+[Al3+]
ppm = number of milligrams present in 1 litre of the solution

Given 
Mass of Al2(SO4)3=3.42 mg
Mass of Na2SO4=1.42 mg

[Al2(SO4)3]=3.42×103342=0.01×103 M
[SO24]=0.03×103 M
[Al3+]=0.02×103 M

[Na2SO4]=1.42×103142=0.01×103 M=[SO24]
[Na+]=0.02×103 M
total concentration of [SO24] =0.04×103 M
Hence in solution
[Na+]=0.02×103 M
[SO24] =0.04×103 M
[Al3+]=0.02×103 M
So,
[Al3+]=[Na+] and [SO24]=[Na+]+[Al3+]
 

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