Which one is not correct for e.m.f. of a galvanic cell?

E_{c e l l} = E_{O P_{a n o d e}} + E_{R P_{c a t h o d e}}

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E_{c e l l} = E_{O P_{L H S}} + E_{R P_{R H S}}

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E_{c e l l} =

higher oxidation potential - lower oxidation potential

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E_{c e l l} =

lower oxidation potential - higher oxidation potential

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Solution

The correct options are
A $E_{c e l l} = E_{O P_{a n o d e}} + E_{R P_{c a t h o d e}}$
B $E_{c e l l} = E_{O P_{L H S}} + E_{R P_{R H S}}$
C $E_{c e l l} =$ higher oxidation potential - lower oxidation potential
The correct expressions for the standard cell potentials of a galvanic cell are as given below.
$E_{c e l l} = E_{O P_{a n o d e}} + E_{O P_{c a t h o d e}}$
$E_{c e l l} = E_{O P_{L H S}} + E_{O P_{R H S}}$
$E_{c e l l} =$ lower oxidation potential $-$ higher oxidation potential.
Thus, only option D is correct and options A to C are incorrect.

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Similar questions

The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is:
$M (s) | M^{+}$ (aq;0.05 molar)|| $M^{+}$ (aq;1 molar)|M(s)
For the above electrolytic cell the magnitude of the cell potential $| E_{c e l l} | = 70 m V$ .