Which one is the Swarts reaction from the following?

C H_{3} B r + N a I A c e t o n e ⟶ C H_{3} I + N a B r

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C H_{3} C l + N a I A c e t o n e ⟶ C H_{3} I + N a C l

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C H_{3} B r + A g F ⟶ C H_{3} F + A g B r

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2 C H_{3} C l + 2 N a D r y e t h e r ⟶ C H_{3} - C H_{3} + 2 N a C l

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Solution

The correct option is C $C H_{3} B r + A g F ⟶ C H_{3} F + A g B r$
When alkyl bromide or iodide are treated with metallic fluorides like $A g F, H g F_{2}$ , etc., they formed alkyl fluoride. This reaction is called Swarts reaction and is an important method for the preparation of fluoroalkanes.

Thus, among the given reactions, Swarts reaction is:

$C H_{3} B r + A g F \to C H_{3} F + A g B r$

Note: Swart's reaction is a type of halogen exchange reaction.

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