Which one of the above oxidation curve is wrongly presented in the given Gibbs free energy vs temperature graph ?

C \to C O_{2}

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T i \to T i O_{2}

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P b \to P b O

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M g \to M g O

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Solution

The correct option is B $T i \to T i O_{2}$
$T i (s) + \frac{1}{2} O_{2 (g)} Δ - \to T i O_{2} (s)$

By increasing temperature,

According to $Δ G = Δ H - T Δ S, Δ G$ for formation of $T i O_{2}$ will move toward +ve value.

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