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Question

Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states? [CBSE AIPMT 2009]


A

3d3,4s2

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B

3d5,4s1

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C

3d5,4s2

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D

3d2,4s2

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Solution

The correct option is C

3d5,4s2


The sum of number of electrons (unpaired) in d-orbitals and number of electrons in s-orbital gives the number of oxidation states (os) exhibited by a d-block element. Therefore,
(a) 3d3,4s2OS=3+2=5
(b) 3d5,4s1OS=5+1=6
(c) 3d5,4s2OS=5+2=7
(d) 3d2,4s2OS=2+2=4
Hence, element with 3d5,4s2 configuration exhibits largest number of oxidation states.


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