Which one of the following conversions involve change in both hybridisation and shape?

C H_{4} \to C_{2} H_{6}

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N H_{3} \to N H_{4}^{+}

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B F_{3} \to B F_{4}^{-}

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H_{2} O \to H_{3} O^{+}

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Solution

The correct option is C $B F_{3} \to B F_{4}^{-}$
Answer:

Option A - $C H_{4} a n d C_{2} H_{6} = s p^{3}$ hybridisation and have tetrahedral shape.

Option B - $N H_{3} a n d N H_{4}^{+} = s p^{3}$ hybridisation and have trigonal pyramidal in $N H_{3}$ and tetrahedral in $N H_{4}^{+} .$

Option C - $B F_{3} = s p^{2}$ hybridisation with trigonal planar shape. $B F_{4}^{-} = s p^{3}$ hybridised and tetrahedral in shape.

Option D - $H_{2} O a n d H_{3} O^{+} = s p^{3}$ hybridization with bent shape for $H_{2} O$ and trigonal pyramidal for $H_{3} O^{+} .$

Option C is correct, as in this option there is change in hybridization and shape.

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Similar questions

Which of the following conversions involve change in both shape and hybridisation?

a) CH4 -> C2H6

b) NH3 -> NH4+

c) BF3 -> BF4-

d) H2O ->H3O+

109^{\circ} 28^{^{'}}

C H_{4}

N H_{4}^{+}

N H_{3}

H_{2} O

F_{2} O

C l_{2} O

C l O_{2}

N F_{3}

C F_{4}

P C l_{5}

N O_{2}

S O_{4}^{2 -}

C H_{2} F_{2}

S F_{6}

B F_{4}^{-}

C F_{3} C l

H_{2} S

P H_{3}

S O F_{4}

P F_{2} C l_{3}

B F_{3} + N H_{3} \to N H_{3}^{+} - B F_{3}^{-}

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