Question

Which one of the following has the maximum number of unpaired electrons ?

• A. $M{g}^{2+}$
• B. $T{i}^{3+}$
• C. $V^{3+}$
• D. $F{e}^{2+}$

Answer 1

The correct option is D $F{e}^{2+}$

No of unpaired electron in different ions are as under :

$M{g}^{2+}\to 1s^2,2s^{2}2p^6,3s^0=0$ Unpaired electron

$T{i}^{3+}\to 1s^2,2s^{2}2p^6,3s^{2}3p^{6}3d^1,4s^0=1$ Unpaired electron

$V^{3+}\to 1s^2,2s^{2}2p^6,3s^{2}3p^{6}3d^2,4s^0=2$ Unpaired electron

$F{e}^{2+}\to 1s^2,2s^{2}s{p}^6,3s^{2}3p^{6}3d^6,4s^0=4$ Unpaired electron
option d is the correct answer