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Hydrogen Peroxide

Which one of ...

Question

Which one of the following is reduced by $H_{2} O_{2}$ in alkaline medium?

A

F e^{2 +}

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B

H O C l

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C

K M n O_{4}

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D

P b S

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E

M n^{2 +}

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Solution

The correct option is D $K M n O_{4}$
$K M n O_{4}$ reduced to $M n O_{2}$ in the presence of $H_{2} O_{2}$ in alkaline medium.

Therefore, $2 M n O_{4}^{-} + 3 H_{2} O_{2} \to 2 M n O_{2} + 3 O_{2} + 2 H_{2} O + 2 O H^{-}$

Hence, option $C$ is correct.

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Similar questions

100

0.01 M

K M n O_{4}

100

H_{2} O_{2}

in acidic medium. The volume of the same

K M n O_{4}

required in alkaline medium to oxidize

100

H_{2} O_{2}

M n O_{4}^{⊝}

M n^{2 +}

in acidic medium and to

M n O_{2}

in alkaline medium)

100

H_{2} O_{2}

100

0.01 M

K M n O_{4}

in acidic medium (

M n O_{4}^{⊝}

M n^{2 +}

100

H_{2} O_{2}

V

0.01 M

K M n O_{4}

in basic medium (

M n O_{4}^{⊝}

M n O_{2}

V

Q. The number of moles of

K M n O_{4}

reduced by one mole of

K I

in alkaline medium is:

For titrating certain volume of a reducing substance by

1 M

K M n O_{4}

, it is found that

20

mL was used in acidic medium,

33.4

mL was used in alkaline medium and

100

mL was used in neutral medium.

{M n O_{4}}^{-}

M n^{2 +}

in acidic Medium.

To what oxidation state is

{M n O_{4}}^{-}

reduced to in alkaline medium?

Q. In an alkaline medium,

K M n O_{4}

reacts as follows (At wt. of

K = 39.09

M n = 54.94

O = 16.0

2 K M n O_{4} + 2 K O H \to 2 K_{2} {M n O}_{4} + H_{2} O + [O]

i) The equivalent weight of

K M n O_{4}

in alkaline medium is 158.
ii) The number of electrons gained by one molecule of

K M n O_{4}

in the alkaline medium is 1.
iii) In the alkaline medium,

K M n O_{4}

acts as a reducing agent.

Select the correct option.

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