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Question

Which one yields the maximum energy?

A
Krebs cycle
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B
Anaerobic respiration
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C
Glycolysis
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D
Aerobic respiration.
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Solution

The correct option is B Aerobic respiration.
Maximum number of ATP is generated per glucose molecule oxidation by aerobic respiration.
Glycolysis gives 2 ATP by substrate-level phosphorylation and 2 NADH yields 6 ATP (assuming 3 ATP per NADH) by oxidative phosphorylation, Transition Reaction gives 2 NADH yields 6 ATP (assuming 3 ATP per NADH) by oxidative phosphorylation, citric acid cycle gives 2 ATP from substrate-level phosphorylation, 6 NADH yields 18 ATP (assuming 3 ATP per NADH) by oxidative phosphorylation, 2 FADH2 yields 4 ATP (assuming 2 ATP per FADH2) by oxidative phosphorylation. So the total maximum yield of ATP generated from one glucose molecule is 38 ATP: 4 from substrate-level phosphorylation; 34 from oxidative phosphorylation.
So the correct option is 'Aerobic respiration'.

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