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Question

Which optically active compound on reduction with $$\displaystyle LiAlH_{4}$$ will give optically inactive compound?


A
CH3CH(OCH3)COOH
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B
CH3CH2CH(OH)COOH
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C
CH3CH2CH(CH2OH)COOH
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D
CH3CH(OH)CH2COOH
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Solution

The correct option is C $$CH_3-CH_2-CH(CH_2OH)-COOH$$
1950189_125130_ans_404371d9c9b048eca2fabfd91acad0df.jpg

Chemistry
NCERT
Standard XII

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