Which optically active compound on reduction with $L i A l H_{4}$ will give optically inactive compound?

C H_{3} - C H (O C H_{3}) - C O O H

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C H_{3} - C H_{2} - C H (O H) - C O O H

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C H_{3} - C H_{2} - C H (C H_{2} O H) - C O O H

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C H_{3} - C H (O H) - C H_{2} - C O O H

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Solution

The correct option is C $C H_{3} - C H_{2} - C H (C H_{2} O H) - C O O H$

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Similar questions

C H_{3} - C H (O H) - C H (O H) - C O O H

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{3} - C O O H

C H_{2} = C H - C O O H

C_{6} H_{5} - C O O H

C_{6} H_{5} - C H_{2} - C O O H

C H_{3} - C H_{2} - C O O H

C H_{3} - C H | O H - C O O H

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

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