Which reaction does not represent auto redox or disproportionation reaction?

C I_{2} + O H^{-} \to C l^{-} + C l O_{3}^{-} H_{2} O

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2 H_{2} O_{2} \to H_{2} O + O_{2}

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2 C u \to C u^{2 +} + C u

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(N H_{4})_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O

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Solution

The correct option is C $(N H_{4})_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O$
A reaction which involves both reduction and oxidation is called as a redox reaction.
So option (D) is the answer.

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Similar questions

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

Z n + C u S O_{4} ⟶ Z n S O_{4} + C u

2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O

2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

Z n + C u S O_{4} ⟶ Z n S O_{4} + C u

2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O

2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

(N H_{4})_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O

(N H_{4})_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O

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