Which reaction shows oxidising nature of $H_{2} O_{2}$ ?

A g_{2} O + H_{2} O_{2} \to A g + H_{2} O + O_{2}

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M n O_{2} + H_{2} O_{2} + H_{2} S O_{4} \to M n S O_{4} + 2 H_{2} O + O_{2}

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P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O

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K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} \to K_{2} S O_{4} + 2 C r O_{5} + 5 H_{2} O

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Solution

The correct option is D $K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} \to K_{2} S O_{4} + 2 C r O_{5} + 5 H_{2} O$
For (A), ${A g}_{2}^{+ 1} O$ is reduced to $A g^{o}$
Therefore, $H_{2} O_{2}$ acts as a reducing agent.

For (B) ${M n}^{+ 4}$ is reduced to ${M n}^{+ 2}$
Here, $H_{2} O_{2}$ acts as a reducing agent.

For (C), There is no change in oxidation state of $P b$ .

For (D), $C r^{+ 6}$ is oxidised to $C r^{+ 10}$ .
Therefore, $H_{2} O_{2}$ acts as an oxidising agent.

Answer: (D) $K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} ⟶ K_{2} S O_{4} + 2 C r O_{5} + 5 H_{2} O$

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Similar questions

Which of the following reaction shows the reduction reaction of $H_{2}$ $O_{2}$ ?

P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O

H_{2} O_{2}

A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2}

In the reaction $A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2} . H_{2} O_{2}$ acts as :

P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O

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