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Question

Which term of the AP 3, 15, 27, 39, .... will be 132 more than its ​54th term?



Solution

The correct option is D

a=3
d=153=12
Let the required term be the ​nth term.
an=a+(n1)d
a54+132=(32+53×12)+132
a54+132=32+636+132
a54+132=800=an
Now,
800=32+(n1)12
768=(n1)12n1=76812=64n=64+1=65
 Thus, 65th term is 132 more than 54th term.

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