CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Which term of the AP 3,15,27,39,......... will be 132 more than its 54th term?

A
60
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
62
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
65
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
63
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 65
Given series is 3,15,27,39.....
We know,
nth term an=a+(n1)d

a= First term
d= Common difference between consecutive terms
n= number of terms
an=nth term

Here a=3 and d=153=2715=12

The 54th term of this sequence is
t54=3+(541)12t54=3+636=639
The term which will be 132 more than 639 will be 771.
So, we need to find which term in the sequence is 771.
771=3+(n1)(12)771=3+12n12771=12n912n=780orn=65.
Hence, 771 is the 65th term.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon